Second Term Lesson Note for Week Six
Class : JSS 1
Subject : Mathematics
Topic : Basic Operations
Duration : 80 Minutes
Period : Double Period
Reference Book :
- Essential Mathematics for Junior Secondary School, JSS 1.
- Lagos State Unified schemes of work for Junior Secondary Schools, JSS 1 – 3.
- Online Resources
Instructional Material : Chart showing the basic operation.
Learning Objectives : By the end of the lesson learners will be able to :
i.
ii.
iii.
Content :
BASIC OPERATION
6.1 Adding and Subtraction
When adding or subtracting numbers make sure you know the place values of the numbers. Then write each number underneath the other so that the units (U) figures are in line, all the tens (T), all the hundreds (H), and so on are in line.
Examples 6.1:
Add 1952 and 567
Take away 936 from 7093
Ade has 5673 marbles, Ola has 3426 marbles, Michael has 887 marbles. How many marbles do they have altogether?
Find the total of 90156, 300673, and 65489.
The difference between two numbers is 6032. If the larger number is 96005, what is the smaller number?
Note: Remember to write the numbers underneath.
Solution:
1. 1 9 5 2 + 5 6 7 =
TH H T U
1 9 5 2
+ 5 6 7
2 5 1 9
2. TH H T U
7 0 9 3
– 9 3 6
6 1 5 7
3. TH H T U
AdesMARBLES 5 6 7 3
OLU’s MARBLES 3 4 2 6
Michael’s MARBLES + 8 8 7
ALTOGETHER 9 9 8 6
4. H.TH T.TH TH H T U
3 0 0 6 7 3
9 0 1 5 6
+ 6 5 4 8 9
4 5 6 3 1 8
5. T.TH TH H T U
9 6 0 0 5 + * * * * *
6 0 3 2
9 6 0 0 5 – 6 0 3 2
8 9 9 7 3
EVALUATION : DO THESE
1. Find the total of 453323, 642176, 99510
2. Take away 301653 from 887321
3. Find the sum of 666721, 55432, 29255, 387, 554 and 77
4. MICHEAL collected 1350 oranges from her sister Helen. He gave 546 to Mathew and 123 to Kenny. How many oranges left in Micheal hands?
CONCLUSION : The teacher summarizes the lesson for a better understanding and marks the learners note.
ASSIGNMENT :
PAGE 12, EXERCISE 2.2 NO. 1 (A, D), N0 10, 12, AND 14.
6.2 Multiplication and Division Of Numbers
Example 6.2 :
1. Find the product of 8600 and 150
2. A big company recently bought 78 new computer each costing #95 000. How much did the company spent?
3. Divide 15648 by 12
4. 5982 computers are to be shared among 40 schools. How many will each school get and how many will be left over?
Solution :
8 6 0 0
x 1 5 0
0 0 0 0 + 4 3 0 0 0
8 6 0 0
1 2 9 0 0 0 0
2. 9 5 0 0 0
x 7 8
7 6 0 0 0 0
6 6 5 0 0 0 0.
6 7 2 6 0 0 0 0
3. 1 3 0 4
12 √ 1 5 6 4 8
1 2
3 6
3 6
4 8
4. 1 4 9
40 5 9 8 2
4 0
1 9 8
1 6 0
3 8 2
3 6 0
2 2
Note each school will collects 149 computers and the left over will be 22.
Evaluation :
DO These :
1. Multiply the following :
(a) 6745 by 356
(b) 89760 by 120
2. Find the product of 98700 and 4900
3. Divide the following :
(a) 56748 by 24
(b) 640000 by 80
4. 789 oranges are to be shared equally among 14 brothers. How many will each person get and how many will remain?
Conclusion : The teacher marks the learners notebook and makes necessary corrections.
ASSIGNMENT :
PAGE 16 EXERCISE 2.6 No. 3, 4 and 5.
This is very nice and i am grateful for explaining basic operation for me. May God bless you all in Jesus name amen
Amen!!!