Third Term Lesson Note for Week Two
Class : JSS 1
Subject : Mathematics
Topic : Revision /Simple Equations
Duration : 80 Minutes
Period : Double Period
Reference Book :
- Essential Mathematics for Junior Secondary School, JSS 1.
- New General Mathematics for Junior Secondary Schools, JSS 1.
- Lagos State Unified schemes of work for Junior Secondary School, JSS 1 – 3.
- Online Resources
Instructional Material : Chart showing the simple Equations
Learning Objectives : By the end of the lesson learners will be able to
i. Define simple Equation
ii. Give examples of simple equations
iii. Distinguish between true and false open sentences.
iii. Solve simple Equations with one or two variables.
Previous Knowledge : Learners have idea on open sentences and finding unknown in any given Equations.
Content :
SIMPLE EQUATION
This expression 3 x p= 18 is an algebraic sentence. It means three times an unknown number is equal to eighteen.
Translate the following equations into words.
5x + 7 = 37 ( It means if 7 is added to five times a number, the result is 37)
11 = 3x – 1. ( It means 11 is equal to 3 times a certain number minus One) .
TRUE AND FALSE STATEMENT
Examples : State whether the following is true or false
i. x + 8 = 15 ( when x is 7)
ii. 3x – 4 = 11 ( when x is 6)
Solution :
x + 8 = 15
7 + 8 = 15. Therefore the statement is true.
Solution :
3x – 4 = 11
3*6 – 4 = 11
18 – 4 = 14 therefore the statement is false.
LINEAR EQUAUTION WITH MIXED OPERATION AND COLLECTION OF LIKE TERMS
When the operation are more than one,
1. Eliminate the unwanted terms by either adding or subtraction
2. Then eliminate the coefficient of the unknown by either multiplying or dividing.
For Examples :
Example 1 : 4y – 5 = 7
Solution :
Using the balance method, we
Add 5 to both sides
4y – 5 + 5 = 7 + 5
4y = 12
Divide both sides by the coefficient of the unknown
4y/4 = 12/4
Therefore, y = 3
Example 2 : 5x -10 = 15x – 60
Solution
5x – 10 = 15x – 60
Collect the like terms
5x -15 x = – 60 + 10
– 10x = – 50
Divide both sides by -10 (Coefficient of the unknown)
-10x/-10 = -50/ -10
Therefore, x = 5.
Presentation Steps :
Step 1 : The teacher revises the previous terms work with the learners and some corrections to the Second Term Examination.
Step 2 : Introduces the lesson by asking the learners to define simple Equation with illustrations.
Step 3 : Identify different types of equations and define key terms used in any given equation.
Step 4 : Solve some examples and calls the learners to solve similar problems on the board one after the other.
Step 5 : State the processes or procedure involved in solving simple Equation.
EVALUATION : Do these,
1. Say whether the following are true or false.
i. 5x = 15 when x =3
ii. x – 2 = 9 when x = 10
iii. 23 – x = 20 when x =3
iv. 24 ÷ x = 4 when x = 4
v. 15 = x – 2 when x = 17
2. Solve the following equations
1.) 6m + 2 = 20 + 5m
2.) 4c – 8 = 10 – 5c
3.) 5x +5 = 35+ 2x
4.) 56 +7y = 5y + 16
CONCLUSION : At the end of the lesson, the teacher summarizes the salient points for a better understanding. He/she goes round to mark the learners notebooks and makes necessary corrections.
ASSIGNMENT :
1. Solve
a. 7x = 28 b. y/3 = 4
c. M – 1 = 6 d. 7 1/2 = 2/3q
2. Use the balance method to solve the following :
i. 7x + 5 = 40 ii. 3x – 13 = 0
iii. 26 = 3q + 5 iv. 10 = 8y – 52